United States presidential election in Pennsylvania, 1988
Main article: United States presidential election, 1988
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The 1988 United States presidential election in Pennsylvania took place on November 8, 1988 throughout all 50 states and D.C., which was part of the 1988 United States presidential election. Voters chose 25 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania narrowly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. This is the last election where Pennsylvania was carried by the Republican presidential candidate until 2016. This was also the first election since 1932 that Pennsylvania did not vote the same as neighboring New York.
Results
| United States presidential[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | George H. W. Bush | 2,300,087 | 50.70% | 25 | |
| Democratic | Michael Dukakis | 2,194,944 | 48.39% | 0 | |
| Consumer | Eugene McCarthy | 19,158 | 0.42% | 0 | |
| Libertarian | Ron Paul | 12,051 | 0.27% | 0 | |
| New Alliance | Lenora Fulani | 4,379 | 0.10% | 0 | |
| America First | David Duke | 3,444 | 0.08% | 0 | |
| Workers' League | Edward Winn | 2,188 | 0.05% | 0 | |
References
See also
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